(x^2+2x-3)(x^2+2x-2)=6

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Solution for (x^2+2x-3)(x^2+2x-2)=6 equation:



(x^2+2x-3)(x^2+2x-2)=6
We move all terms to the left:
(x^2+2x-3)(x^2+2x-2)-(6)=0
We move all terms containing x to the left, all other terms to the right
(x^2+2x-3)(x^2+2x-2)=6

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